MY CONCLUSION:

16/3e8=s/c=533us [1.6e-34:e-35] vs sqrt(32/10)=1.8s => ratio 3e-8 , if planck time and gravity on earth/mass body time have the ratio c, it is really prooving (s/c)^2:2s/g=t1:t2 => c, this area A/c:t^2=1 => A1/A2 * t=1 => A_body:A_gfield * 1/t=1 => so if m2 per second : m2 is ONLY area/area per second, it is dimmless per second = 1, YES INTERESTING CONST FOR GRAVITATION 🙂 /\ /\ /\ : _ _ _ =1 when? if /\ = 1/-1 proving gravity has ANTI GRAVITY && => /\ = \/ <= Does dark matter exist then???

That way graviton and anti graviton are dissolving each other:

Looking at simulation it is like graviton is eating anti graviton:

Thanks for simu code to gpt:

using Pkg
Pkg.add("Plots")
using Plots
# veľkosť mriežky
N = 100
steps = 300
D = 0.2        # difúzny koeficient
dt = 0.1       # krok času
# Koncentrácia látky (N×N matica)
C = zeros(Float64, N, N)
# Počiatočná častica – v strede je vysoká koncentrácia
for i in 45:55, j in 45:55
    C[i,j] = 1.0
end
# Funkcia na výpočet Laplaceovho operátora
laplace(C) = circshift(C,(1,0)) + circshift(C,(-1,0)) +
             circshift(C,(0,1)) + circshift(C,(0,-1)) - 4C
# Animácia
anim = @animate for t in 1:steps
    global C
    C .= C .+ D * dt .* laplace(C)

    heatmap(C, title="Dissolution / Diffusion step $t",
            c=:viridis, clims=(0,1))
end
gif(anim, "diffusion2.gif", fps=20)

Lawrence Crowell says: Gravitation is considered to be a very weak force. The Newtonian law of gravitation is that the force between two masses M and m separated by r is F_g = -GMm/r^2 in the radial direction centered at the center of mass of the two masses. Here G = 6.67×10^{-11}Nt-m^2/kg^2 The electric force between two charges F_e = (1/4πε)q_1q_2/r^2. Let us consider two protons, which has a mass of m = 1.67×10^{-27}kg. The electric charge is e = 1.6x10^{-19}coulombs and the dielectric constant of free space is epsilon = 8.8×10^{-12}F/m. Let us take the ratio of the electric and gravitational forces of these two protons F_e/F_g = (1/4πε)e^2/Gm^2 = (9.04×10^9)(1.6×10^{-19})^2/[(6.67×10^{-11})(1.67×10^{-27})^2] = 1.24×10^{36} This is a huge ratio. Now we can easily see that gravitation has a running coupling constant Gm^2 and that if the masses of the protons were equal to the Planck mass. m_p = 2.18×10^{-8}kg that this ratio is ~ 10^2 --- gravitation becomes stronger than the electric field. Now as energy rises the electric field with the fine structure constant alpha ~= 1/137 → 1 and so the two forces are comparable. The weakness of gravitation can be seen as a manifestation of the very small masses of elementary particles relative to the Planck mass. This is how the Earth can have a large gravitational force that is extensive, for the Earth is 6×10^{24}kg in mass. Max Planck worked out the Planck scale by using pure dimensional analysis. However, we can see it as due to the situation where a black hole radius is equal to its own Compton wavelength λ = h/mc. We substitute r = 2GM/c^2 for the Compton wavelength and get 2GM/c^2 = h/Mc or M^2 = hc/G. Now as a correction we make this more precise by letting this Compton wave exist on the black hole surface, give a 2π, or G → 2π G and we bet M^2 = ħc/G and this is the Planck mass m_p = √(ħc/G). Then using standard formula for mass energy = mc^2 and that is conjugate with time via the Planck constant hbar we get ℓ_p = √(Għ/c^3) = 1.6×10^{-35}m, that is the Planck length. Returning to the relative strengths of electromagnetism and gravity, where the calculations are going to be more approximate. Consider the Earth, which is mass 6×10^{24}kg. Two masses with half this mass, centers separated by the Earth's radius r = 6×10^6m the force between these two is F = GM^2/d^2 = (6.7×10^{-11}N-m^2/kg^2)(9×10^{48}kg^2/3.6×10^{13}m^2 = 1.7×10^25N. That is a considerable amount of force. However, this is distributed over an area comparable to the area of the Earth ~ 4πr^2 = 1.6×10^{14}m^2, for a pressure of ~ 10^{11}Pa. Remember, atmospheric pressure is about 10^{5}pa, and so this is around a million atmospheres of pressure. That is about what is known for pressure in the Earth's interior. On a single atom the force on that, area = 4πr^2, r ~ 10^{-11} m, so F ~ 10^{-13}N. Now consider the force between two charges on the scale of an atom ~ 10^{-11}m, where what defines this length is due to quantum mechanics, so the electric force on an atom is, F_e = (9.04×10^9)(1.6×10^{-19})^2N-m^2/10^{-22}m^2 =~ 2.3×10^{-7}M. This is a million times the force that the internal pressure of the Earth can exert against single atoms. In order to crush atoms it requires a million times the mass than the Earth. The rocks and materials deep in the Earth are far from being crushed into collapse. The sun is 2×10^{30}kg or 330,000 times the mass of Earth. Stars around 10 times the mass of the sun can after exhausting their fuel collapse into a neutron star or black hole. The masses of elementary particles are what mediate the strength of gravitation. In another cosmology with more massive particles The ratio of gauge forces and gravitation would be larger. A plausible dimensionless constant for gravitation that reflects this ratio would be the ratio of the Higgs particle mass and the Planck mass or their square so (m_H/m_p)^2 = 1.0×10^{-34}. The reciprocal of this is also comparable to the above ratio. I think this is a good dimensionless constant for gravitation.

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