https://hrubos.tech/blogy/content/images/20260606223826-qubit-problem-resonance-craddle.jpg All right guys, this is the machine trying to tunnel electron particle through the barrier: [...] Read more

0y=22? 0=1+i-1-i, size of Cmplx? (1--1)^2+(i--i)^2 => 4+4i^2==22 => i^2=18/4 => -4.5+i^2 => size cmplx 11.25 => back: 11.25 * (4+4i^2)=22 => 0y>0 => 11.25^2>22; proved; and [...] Read more

vyzerá to na tretiny á teda by som išiel 5.4^2=29.16m2 ten prebytok je zároveň chýbajúci I_ teda dva štvorce ho majú, ale dva ho nemajú, teda sa to vyrovná :) [...] Read more

Today I was reading Mr. Musk and his latency shrinking from 550km orbit towards 350km orbit Star Link. My idea for the simmulation was a string that bounces through the jar full of balls. The thing [...] Read more

počítajme: 2sqrt(2x)=2; sqrt(2x)=1; x==0.5; 1. metóda zlogaritmovanie: 2 * 0.5log(x)=2;2=1+1; log(x)=2log(x);log(x)=0.5; x=0.5; def: log_a(x)=0.5 <=> sqrt(a)=x; a=1 => 1^0.5=1 => x==0.5, [...] Read more

Hľadali ju vedci, inžinieri, profesori. Teória všetkého. A ako môže vôbec existovať, veď rovnica nemá v zápise ľavú stranu. Rovná sa kríž. Čo len to je? Nuž je to aj tá veta: Bohu nič nie je [...] Read more

2log(x)=9 => 3^4.5 => sqrt(3^4) => sqrt(81) => 9=x prečo 9? 9=2^3 * log(10) + 1(x^0), no á to je všetko priatelia ;) [...] Read more

išiel by som postupne, všetko si chladnokrvne premyslím, ak je prvý štvorec sqrt(2)^2, tak druhý musí byť sqrt(2) * iks==4, teda iks = sqrt(2) * 2=3 * sqrt(2) á následne 3/strana sqrt(2) * 2sqrt(2) [...] Read more

Okay, we know quantum fluctuations are present at specific places in atom. These places are called orbitals. Now let's imagine the place where energy must fall down for electron if creating sigma [...] Read more

2y=12; 20+y=2z; 26=2z; z=13=? [...] Read more